From 074dab04cafdb3a1965d27aa77f9e6fa8b62dd4e Mon Sep 17 00:00:00 2001
From: root <root@localhost>
Date: Sat, 3 Oct 2026 23:31:20 +0800
Subject: [PATCH] =?UTF-8?q?fix(identity):=20=E5=AD=A3=E8=A1=A8=E5=8F=AA?=
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Co-Authored-By: Claude Opus 5.5 <noreply@anthropic.com>
Claude-Session: https://claude.ai/code/session_01Cxwgnn2pbzQ7rXv3rq7fei
---
 .../sources-identity/service/episode-resolution.ts       | 9 ++++++++-
 1 file changed, 8 insertions(+), 1 deletion(-)

diff --git a/apps/server/src/modules/sources-identity/service/episode-resolution.ts b/apps/server/src/modules/sources-identity/service/episode-resolution.ts
index 0b346edd..670fcfbd 100644
--- a/apps/server/src/modules/sources-identity/service/episode-resolution.ts
+++ b/apps/server/src/modules/sources-identity/service/episode-resolution.ts
@@ -38,7 +38,11 @@ const ENDED_STATUSES = new Set(["ended", "canceled", "cancelled"]);
 /** 待处理证据里最多列多少条资源 */
 const DECISION_LIST_LIMIT = 50;
 
-/** 作品季表:季号 ≥ 0 的季单元;最新季 = 季号 ≥ 1 的最大季单元 */
+/**
+ * 作品季表:季号 ≥ 0 的季单元;最新季 = 季号 ≥ 1 的最大季单元。
+ * 只计元数据(tmdb)/ 人工(user)来源或已确认的季单元:资源 / 文件懒建的临时季(解析错的 S05 之类)不进季表,
+ * 否则它总集数为空会让该季资源一律按「元数据滞后」放行,还会抬高最新季。
+ */
 export async function loadSeasonTable(exec: Exec, entityId: string): Promise<SeasonTable> {
   const entity = await exec
     .selectFrom("media_entity")
@@ -52,6 +56,8 @@ export async function loadSeasonTable(exec: Exec, entityId: string): Promise<Sea
       "season_number",
       "episode_number",
       "episode_total",
+      "status",
+      "source",
       sql<string | null>`to_char(air_date, 'YYYY-MM-DD')`.as("air"),
     ])
     .where("media_entity_id", "=", entityId)
@@ -63,6 +69,7 @@ export async function loadSeasonTable(exec: Exec, entityId: string): Promise<Sea
   const seasons = new Map<number, SeasonInfo>();
   for (const u of units) {
     if (u.kind !== "season" || u.season_number === null || u.season_number < 0) continue;
+    if (u.status !== "confirmed" && u.source !== "tmdb" && u.source !== "user") continue;
     const cur = seasons.get(u.season_number);
     // 重复季单元(并发懒建遗留)取已知的较大总集数
     const total = u.episode_total ?? null;